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6n^2+1606n-65592=0
a = 6; b = 1606; c = -65592;
Δ = b2-4ac
Δ = 16062-4·6·(-65592)
Δ = 4153444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4153444}=2038$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1606)-2038}{2*6}=\frac{-3644}{12} =-303+2/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1606)+2038}{2*6}=\frac{432}{12} =36 $
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